2007-12-14 11:09:01 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
What if 50% to A and 50% to B is added?
2007-12-14 11:23:16 · update #1
Assume initially the total mass is 1 g. You have
.4 g of A, .3 g of B, and .3 g of C
Since 40% of A is .4 g, 10% of A is .1 g.
A: (.4+.1)/1.1 = 45.4545%
B: .3/1.1 = 27.2727%
C: .3/1.1 = 27.2727%
Total: 100%
2007-12-14 11:19:31 · answer #1 · answered by sahsjing 7 · 1⤊ 0⤋
10% of a = .04
a = 44/104 = 0.423 = 42.3%
b and c = 30/104 = 28.8%
2007-12-14 19:24:11 · answer #2 · answered by norman 7 · 0⤊ 0⤋
original quantities are
A = 0.4
B = 0.3
C = 0.3
total = 1
when 10% A was added
A = 0.4 + 0.4(10/100) = 0.44
B = 0.3
C = 0.3
toatal = 1.04
now new percentages are A = (0.44/1.04)*100 = 42.32%
B = (0.3/1.04)*100 = 28.84%
C = 28.84 %
2007-12-14 19:21:54 · answer #3 · answered by mohanrao d 7 · 0⤊ 0⤋
That depends on what the definition of "was" is.
2007-12-14 19:17:24 · answer #4 · answered by Mark 6 · 0⤊ 0⤋