How would you figure this?
2007-12-14 10:59:29 · 10 answers · asked by cwoo 2 in Science & Mathematics ➔ Mathematics
[(r-3)(r-2)]/[(r+2)(r-2)] =
(r-3)/(r+2)
2007-12-14 11:05:10 · answer #1 · answered by Omega 3 · 0⤊ 0⤋
For All R 2
2016-12-28 13:38:25 · answer #2 · answered by ? 4 · 0⤊ 0⤋
This Site Might Help You.
RE:
For all r not equal to +2 or -2, (r^2 - 5r +6)/(r^2 -4) = ?
How would you figure this?
2015-08-06 03:25:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
numerator = r^2 - 5r + 6 = (r - 3)(r-2)
denominator = r^2 - 4 = (r+2)(r-2)
numerator/denominator = (r-3)(r-2)/(r+2)(r-2)
you can cancel out r-2 since r is not equal to 2
so final answer is = (r-3)/(r+2)
2007-12-14 11:06:44 · answer #4 · answered by mohanrao d 7 · 2⤊ 0⤋
(r-3)/(r+2)
2007-12-14 12:55:20 · answer #5 · answered by J 6 · 0⤊ 0⤋
solve the top part
(r^2 - 5r + 6)=(r-2)(r-3)
r = 3 is the only solution. if r=2 the expression is undefined
2007-12-14 11:03:07 · answer #6 · answered by norman 7 · 0⤊ 0⤋
Factor.
= (r-6)(r+1)/(r+2)(r-2)
2007-12-14 11:01:48 · answer #7 · answered by Kevin 2 · 0⤊ 0⤋
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2015-08-04 05:32:21 · answer #8 · answered by Anonymous · 0⤊ 0⤋
{(r-2)(r-3)}/{(r-2)^2}
(r-3)/(r-2)
since r cannot be +2 (nothing can be divisible by 0)
r must 3
2007-12-14 11:06:41 · answer #9 · answered by SonnyAngel 2 · 0⤊ 0⤋
equals (r-3)/(r+2)
2007-12-14 11:02:47 · answer #10 · answered by hong_wei886 3 · 0⤊ 0⤋