2007-12-14 10:59:00 · 7 answers · asked by pepper 1 in Science & Mathematics ➔ Mathematics
Given line has m = - 2
Perpendicular has m = 1 / 2
y - 7 = (1/2) (x + 4)
y = (1/2)x + 2 + 7
y = (1/2)x + 9
2007-12-17 06:51:26 · answer #1 · answered by Como 7 · 4⤊ 1⤋
dy/dx= -2
since it is perpendicular then the gradient = 1/2
using the pts (-4,7) and m=1/2
substitute into the equ'n y=mx + c
7=(1/2)*(-4) + c
7= -2 + c
9=c
therefore the equation of the line = y=1/2 x + 9
2007-12-14 11:07:53 · answer #2 · answered by lp342 4 · 1⤊ 0⤋
Slope of y=-2x+6 is -2
The perpendicular's slope is therefore 1/2, ( the
negative reciprocal)
The line you seek is y= (1/2)x+b
The line passes through (-4,7)
Therefore substitute -4 for x and 7 for y to find b
7=(1/2)(-4)+b
7=-2+b
b=9
The required equation is y=(1/2)x+9
2007-12-14 11:09:27 · answer #3 · answered by Grampedo 7 · 0⤊ 0⤋
line perpendicular to y = mx + b, passing through (h, k) is
x + my = h + mk
then line perpendicular to y = --2x + 6, passing through (--4, 7)
is
x --2y = --4 --2*7
or x -- 2y + 18 = 0
2007-12-14 11:17:26 · answer #4 · answered by sv 7 · 0⤊ 0⤋
y=-2x + 6
y=mx +b
7=-2(4) +b
7= -8 + b
b=15 -6
b= 9
I think so!
2007-12-14 11:11:24 · answer #5 · answered by $$$$$$$$$$$$$ 2 · 0⤊ 0⤋
You reverse the slope (make it 1/2)
and plug in the point (-4, 7)
This website may help.
http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut15_slope.htm
2007-12-14 11:08:05 · answer #6 · answered by Hillary 1 · 0⤊ 2⤋
(y-7)/(x+4)=1/2
2(y-7)=(x+4)
2y-14=x+4
2y=x+18
y=1/2x+9
2007-12-14 11:05:19 · answer #7 · answered by norman 7 · 1⤊ 0⤋