2007-12-14 10:55:07 · 8 answers · asked by mrsstrick27 2 in Science & Mathematics ➔ Mathematics
b ² - 2 b c + c ²
9 - (2)(3)(-2) + 4
9 + 12 + 4
25
2007-12-17 06:06:50 · answer #1 · answered by Como 7 · 3⤊ 3⤋
If b = 3 and c = -2: b² – 2bc + c² = (3)² - 2(3)(-2) + (-2)² = 9 + 12 + 4 = 25 a extra physically powerful way is to computer screen that b² – 2bc + c² = (b - c)² So if b = 3 and c = -2 then b² – 2bc + c² = (3 - (-2))² = 25 oops nevermind, it extremely is 14
2016-12-11 04:55:54 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Plug the numbers into the equation: 3^2 - 2*3*-2 + -2^2. Then remember the order of operations:
Parentheses: There aren't any. 3^2 - 2*3*-2 + -2^2.
Exponents: Solve 3^2 and -2^2. 9 - 2*3*-2 + 4.
Multiplication/Division: Solve 2*3*-2. 9 - -12 + 4.
Addition/Subtraction: Solve 9 - -12 + 4. Subtracting a negative is the same as adding a positive, so it's 9 + 12 + 4. 25.
So the answer is 25.
2007-12-14 11:01:14 · answer #3 · answered by Amy F 5 · 1⤊ 2⤋
So its just :
3^2 - 2 x 3 x -2 + -2^2
9 + 12 + 4
= 25
2007-12-14 11:03:23 · answer #4 · answered by Anonymous · 1⤊ 2⤋
Hey there!
Two ways.
Here's the first way.
b^2-2bc+c^2 -->
3^2-2(3)(-2)+(-2)^2 -->
9+12+4 -->
25
So the answer is 25.
Here's the second way.
b^2-2bc+c^2 -->
(b-c)^2 -->
(3-(-2))^2 -->
(3+2)^2 -->
5^2 -->
25
Either way the answer is 25.
Hope it helps!
2007-12-14 10:58:10 · answer #5 · answered by ? 6 · 2⤊ 3⤋
b^2-2bc+c^2
3^2-2(3)(-2)+-2^2
9+12+4=25
2007-12-14 12:17:54 · answer #6 · answered by Dave aka Spider Monkey 7 · 1⤊ 3⤋
9-2(-6)+4
9+12+4
=25
Remember that squaring a negative always yelds a positive
2007-12-14 10:59:04 · answer #7 · answered by Juan G 1 · 1⤊ 2⤋
25
Im positive.
2007-12-14 10:57:56 · answer #8 · answered by Brittany 3 · 1⤊ 2⤋