What is the two integers?

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Twice the first of two consecutive integers increased by the square of the second is 78.

2007-12-14 09:03:05 · 4 answers · asked by Bishwanath S 1 in Science & Mathematics ➔ Mathematics

n - m = 1
n*n + 2m = 78

n*n + 2(n-1) = 78

n*n + 2n - 80 = 0

n = -1 +/- sqrt(1 + 80)
n = -1 +/- 9
n = -10, 8
m = -11, 7

2007-12-14 09:14:14 · answer #1 · answered by none2perdy 4 · 0⤊ 0⤋

7 and 8

2*7 = 14 8 ^2 = 64 14 + 64 = 78

2007-12-14 17:12:26 · answer #2 · answered by Prophet 1102 7 · 0⤊ 0⤋

7 and 8

2007-12-14 17:47:49 · answer #3 · answered by LilC 2 · 0⤊ 0⤋

2x + (x + 1)^2 = 78
=> x^2 + 4x -- 77 = 0
=> (x + 11)(x -- 7) = 0
giving x = -- 11, 7
integers are either --11 and --10 OR 7 and 8

2007-12-14 17:11:57 · answer #4 · answered by sv 7 · 0⤊ 0⤋