The diagonal of a tv set is 26 inches long. Its length is 14 inches more that the height. Find the dimensions of the TV set
2007-12-14 07:37:36 · 5 answers · asked by Sampson M 1 in Education & Reference ➔ Homework Help
Pythagorean theorem
a^2 + b^2 = c^2
So
H^2 + (H+14)^2 = 26^2
2H^2 + 28H + 196 = 676
2H^2 +28H -480 = 0
H^2 +14H - 240 = 0
(H + 24) (H- 10) = 0
H = 10
L = 24
2007-12-14 07:40:35 · answer #1 · answered by ignoramus 7 · 0⤊ 0⤋
Use the Pythagorean Theorm: a^2 +b^2=c^2 where c is the diagonal of the TV screen,(26), and 14 is one of sides of the triangle.
14^2 + b^2=26^2
196 + b^2=26^2
B^2= 26^2- 196
B= sq. rt 26^2 -196
B=sq rt 676-196
B=sqrt 480
B=sq rt 16* 30
b=4sq rt 30
2007-12-14 15:51:35 · answer #2 · answered by oldteacher 5 · 0⤊ 0⤋
Using Pythagorean theorem, a^2+b^2=c^2
so we know c which = 26"
26^2=676
a^2+b^2=676
but b=a+14
so,
a^2+(a+14)^2=676
a^2+a^2+14a+196=676
2a^2+14a=480
Then break it down and solve
height=10 and length=24
2007-12-14 15:52:12 · answer #3 · answered by darb_cu 3 · 0⤊ 0⤋
Product Dimensions: 26 x 10.8 x 21.1 inches ; 32.8 pounds
2007-12-14 15:41:42 · answer #4 · answered by god knows and sees else Yahoo 6 · 0⤊ 0⤋
6 in.
2007-12-14 15:42:53 · answer #5 · answered by Anonymous · 0⤊ 0⤋