1. In a molecule in which the central atom exhibits sp3d2 hybrid orbitals, the electron pairs are directed toward the corners of:
(A) a tetrahedron
(B) a square-based pyramid
(C) a trigonal bipyramid
(D) a square
(E) an octahedron
Someone told me that it was E) an octahedron but I don't understand why. Can someone else why it's an octahedron and not any of the others? I'm confused...thanks so much.
2007-12-14 06:12:57 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Well it could be both Trigonal Bipyramid and Octahedron. The no. of atoms to form such structures would be 6 with octahedron requiring 6 SIMILAR bonds. If the bonds were the same, we would call it a Trigonal Bipyramid
2007-12-14 06:23:53 · answer #1 · answered by w4c~m3-5un 3 · 0⤊ 3⤋
The electron pairs are directed toward the corners of an octahedron. Always true for six electron pairs (domains), which is always sp3d2.
2007-12-14 06:34:00 · answer #2 · answered by Anonymous · 1⤊ 1⤋
it is octahedral but more specifically it would be square planar so D.
go over the VSPER model, i think its just a matter of memorizing whats what.
2007-12-14 06:19:05 · answer #3 · answered by Anonymous · 0⤊ 2⤋
the answer is in the link
2007-12-14 06:20:28 · answer #4 · answered by maussy 7 · 1⤊ 2⤋