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2007-12-14 05:51:12 · 5 answers · asked by Anthony R 1 in Science & Mathematics Mathematics

5 answers

3X2 = 6 think of it 7x must be zero. x must be zero as any number times zero is zero.

2007-12-14 06:02:29 · answer #1 · answered by redhotboxsoxfan 6 · 0 0

I'm assuming you mean
3x^2 + 7x = 6
Rewrite as:
3x^2 + 7x - 6 = 0

I would use the quadratic formula:
x = {-b +/- sqrt(b^2 - 4ac)}/2a

In your case a = 3, b = 7, c = -6.

Just plug them into quadratic formula and you have the answers (you'll get 2 answers, since the equation is quadratic).

2007-12-14 06:02:29 · answer #2 · answered by KG06 3 · 0 0

the respond is -a million, and four/3. you will get the respond 2 techniques. First ingredient the equation into 2 areas (3x - 4) * (x + a million) = 0 and then sparkling up for 0. any incorrect way is to apply the quadratic equation it somewhat is x = (-b +- sqrt(b^2 - 4ac)) / 2a, the place a is this occasion may be 3, b may be -a million, and four may be -4 that are the coefficeints to the equation.

2016-11-26 23:42:13 · answer #3 · answered by ? 4 · 0 0

Hi,
Just write this in the standard form and factor it:
3x²+7x-6=0
(3x-2)(x+3) = 0
3x-2 = 0
3x=2
x=2/3
x+3=0
x=-3

FE

2007-12-14 06:09:35 · answer #4 · answered by formeng 6 · 0 0

consider , x^2+ ax - b= 0
a = 7/3 , b = 2 ;

x1 = -a/2-sqrt ( a^2+4ab)
x2 = -a/2+sqrt ( a^2+4ab)

2007-12-14 06:10:19 · answer #5 · answered by Nur S 4 · 0 0

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