A painter has 7 paintings he considers his best. He is asked to submit one painting to each of three painting contests to be held in New York, Los Angeles, and Kansas City. In how many ways can he choose to submit four of his paintings
2007-12-14 04:54:06 · 5 answers · asked by jewel7962002 1 in Science & Mathematics ➔ Mathematics
There are 7 × 6 × 5 = 210 ways of sending the picture.
2007-12-14 04:57:12 · answer #1 · answered by Pranil 7 · 0⤊ 0⤋
Assuming the paintings are all distinctly different,
He has 7 choices for the first contest,
leaving 6 choices for the second contest,
leaveing 5 choice for the third contest
7*6*5 = 210 ways.
Your last sentence in your question is confusing, I assume you meant three instead of four.
2007-12-14 05:01:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I thought you need him to submit *three* of his paintings.
7 choices for the 1st painting (to NY)
6 choices for the 2nd painting (to LA)
5 choices for the 3rd painting (to KC)
7 x 6 x 5 = 210 ways
Note: This assumes that it matters which city gets which painting. Sending painting A to NY, B to LA and C to KC is *different* than sending painting C to NY, A to LA and B to KC, even though they are the same 3 paintings.
2007-12-14 04:57:46 · answer #3 · answered by Puzzling 7 · 0⤊ 0⤋
24
2007-12-14 04:56:28 · answer #4 · answered by KEYNARDO 5 · 0⤊ 0⤋
The first choice is one out of 7 the next one out of 6 the next one out of 5. Submiting 3 would be 7x6x5=210 combinations. (hopefully he has some friends to help him choose.... he could have them vote, then tally the votes (retaining veto power of course in case he decides at the last minute what he wants to do)
2007-12-14 04:59:38 · answer #5 · answered by hasse_john 7 · 0⤊ 0⤋