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66 + 33√6 / 11

a. 6 + 3√6
b. 6 - 3√6
c. 9√6
d. 9√6 / 11

2007-12-14 04:32:34 · 3 answers · asked by . 1 in Science & Mathematics Mathematics

3 answers

It's a little confusing whether the 11 applies to the whole sum or not. I'll assume you meant:

(66 + 33√6) / 11

Divide the individual terms by 11:
6 + 3√6

You can't add disparate terms and you can't reduce the square root further. This matches with the first answer:
A) 6 + 3√6

2007-12-14 04:41:45 · answer #1 · answered by Puzzling 7 · 0 0

66 + 33√6 / 11
= 66/11 + 33√6 / 11
= 6 + 3√6
a. 6 + 3√6

2007-12-14 12:39:39 · answer #2 · answered by Pranil 7 · 0 0

it is a.

2007-12-14 12:41:42 · answer #3 · answered by michael c 3 · 0 0

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