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√81 + √32 + √64 + √18

a. √32 + √18 + 17
b. 7√2 + √81 + √64
c. 7√2 + 17
d. 25√2 + 17

2007-12-14 03:34:58 · 8 answers · asked by peachy 1 in Science & Mathematics Mathematics

8 answers

9 + 4√2 + 8 + 3√2
7√2 + 17
OPTION c

2007-12-14 03:57:28 · answer #1 · answered by Como 7 · 2 0

√81 + √32 + √64 + √18

= 9 + √16*2 + 8 + √9*2

= 17 + 4√2 + 3√2

= 17 + 7√2

The answer is
" c) 7√2 + 17"

2007-12-14 12:49:08 · answer #2 · answered by 123 1 · 0 1

√81 + √32 + √64 + √18


√81 = √9√9 = 3(3) = 9

√32 = √16√2 = 4√2

√64 = √4√16 = 2(4) = 8

√18 = √9√2 = 3√2

Adding

17 + 7√2

2007-12-14 11:43:17 · answer #3 · answered by kindricko 7 · 0 0

√81 + √32 + √64 + √18

√81 = √(9^2) = 9
√32 = √(2^5) = √(2^2) * √(2^2) * √2 = 2 * 2 * √2 = 4√2
√64 = √(2^6) = (√(2^2))^3 = 2^3 = 8
√18 = √(3^2 * 2) = √(3^2) * √2 = 3√2

9 + 4√2 + 8 + 3√2 = 7√2 + 17 = c

2007-12-14 11:47:05 · answer #4 · answered by battleship potemkin AM 6 · 0 0

=9+4√2+8+3√2
=4+3(√2)+9+8
=7√2+17

2007-12-14 11:44:13 · answer #5 · answered by Uttam 1 · 0 0

√81 + √32 + √64 + √18
√(9)^2 + √(4)^2*2 + √(8)^2 + √(3)^2*2
9+4√2+8+3√2
9+8+4√2+3√2
17+7√2

2007-12-14 11:40:15 · answer #6 · answered by Siva 5 · 0 0

rt 81 + rt32 + rt64 + rt18

= 9 + 4rt2 + 8 + 3rt2

= 17 + 7rt2.

2007-12-14 11:38:47 · answer #7 · answered by Twiggy 7 · 0 0

sqrt of81+sqrt of 32+sqrt of 64+sqrt of 18=
9+4sqrt of2+8+3 sqrt of 2=
17+7sqrt of 2

c.

2007-12-14 14:07:51 · answer #8 · answered by Dave aka Spider Monkey 7 · 0 1

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