specific heat/heat of fusion problem?

Question

A 2 kg cube of iron at 300 C is placed on a 5 kg block of ice at 0 C. How much ice will change to liquid water at 0 C the specific heat of iron is 450 and the heat of fusion of ice is 3.34x10^5

Answer 1

The energy required to change the temperature of a substance with no state change involved is

Q = m c ΔT

The energy required to change the state of a substance at constant temperature is

Q = m L

So compute the energy required to cool the iron down to 0 degrees. Compare that with the energy required to melt all of the ice. If it's less, then you can figure out how much ice melted. If it's more, all of the ice melts into water and the water warms up, and you need to find the final temperature of what will be iron and water.