2007-12-14 03:12:24 · 10 answers · asked by Nicholas L 1 in Science & Mathematics ➔ Mathematics
- 4 - 10 + 5 i - 7 i
- 14 - 2 i
(- 2) (7 + i)
2007-12-14 03:32:20 · answer #1 · answered by Como 7 · 3⤊ 0⤋
Simplifying
(-4 + -7i) + -1(10 + -5i)
Remove parenthesis around (-4 + -7i)
-4 + -7i + -1(10 + -5i)
-4 + -7i + (10 * -1 + -5i * -1)
-4 + -7i + (-10 + 5i)
Reorder the terms:
-4 + -10 + -7i + 5i
Combine like terms: -4 + -10 = -14
-14 + -7i + 5i
Combine like terms: -7i + 5i = -2i
-14 + -2i
2007-12-14 03:19:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
subtract like terms, as if the i's were x's:
-4 - 7i - 10 + 5i =
-14 - 2i
2007-12-14 03:18:01 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
-4-7i - 10 +5i
= -14 -2i
2007-12-14 03:19:16 · answer #4 · answered by Sciman 6 · 0⤊ 0⤋
(-4-7i)-(10-5i) = -4-7i-10+5i = -14-2i = -2(7+i)
2007-12-14 03:25:06 · answer #5 · answered by Peyman 2 · 0⤊ 0⤋
(-4-7i)-(10-5i)
= -4-7i -10 +5i
= -14 - 2i
= -2( 7+i)
There you have it!!
2007-12-14 03:18:10 · answer #6 · answered by k_libranwrath 1 · 0⤊ 0⤋
(-4-7i)-10+5i (because if you got a "-" before brackets the "-" changes into a "+"
solution:
-14-2i
2007-12-14 03:20:26 · answer #7 · answered by buccaneers 2 · 0⤊ 0⤋
(-4-7i)-(10-5i)=
-4-7i-10-5i or
combine like terms
(-4-10)+(-7i-5i)
-14-12i
2007-12-14 03:23:44 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Ans is -14-2i
2007-12-14 03:19:12 · answer #9 · answered by mohit_oena 1 · 0⤊ 0⤋
i is the sq. root of -a million, and in case you have (sqrt(-a million))^2 then you particularly only get -a million. so case in point, #24 you have i*i*i*i....*i 11 instances, so interior the top you may have only -i. so pleaseeee do your homework your self.
2016-11-26 23:17:48 · answer #10 · answered by mehaffey 4 · 0⤊ 0⤋