(11-square root of -5)(-4+ square root of -5)
A=-39+15i square root (5) B=-39-15i square root (5)
C=39+15(5) D= 39+15i square root 5
2007-12-14 03:08:11 · 7 answers · asked by ivan m 2 in Science & Mathematics ➔ Mathematics
the answer is A.
-44+11sq.rt.-5+4sq.rt.-5-(-5)
-44+15sq.rt.-5+5
-39+15sq.rt.-5
-39+15isq.rt.5
2007-12-14 03:16:00 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Answer is A -39+15i square root (5)
2007-12-14 11:15:38 · answer #2 · answered by mohit_oena 1 · 0⤊ 0⤋
(11 - â-5)(-4 + â-5) =
(11 - iâ5)(-4 + iâ5) =
-44 + 4iâ5 + 11iâ5 - i²(â5)² =
-44 + 15iâ5 + 5 =
-39 + 15iâ5
2007-12-14 11:16:05 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
the answer is a
-39 + 15i square root (5)
2007-12-14 11:16:02 · answer #4 · answered by soccerdude 1 · 0⤊ 0⤋
(11- â-5)(-4 + â-5)
=>(11 -iâ5)(-4 +iâ5) (since â-1 = i)
expand
11(-4 + iâ5) - iâ5(-4 + iâ5)
=>(-44 +11i â5) + 4iâ5 - 5i^2)
=>-44 + 15iâ5) + 5) (since i^2 = -1)
=> -39 + 15â5 i
2007-12-14 11:23:45 · answer #5 · answered by mohanrao d 7 · 0⤊ 0⤋
get a calculator. If that doesn't work ask your teacher
2007-12-14 11:10:40 · answer #6 · answered by The Flying Porcupine 2 · 0⤊ 1⤋
I think it's "A"
2007-12-14 11:19:53 · answer #7 · answered by Anonymous · 0⤊ 0⤋