Physics-Please Help if you can!(10)?

Question

A spring has a force constant of 430.0 N/m.

(a) Determine the potential energy stored in the spring when the spring is stretched 4.16 cm from equilibrium.
J
(b) Determine the potential energy stored in the spring when the spring is stretched 3.32 cm from equilibrium.
J
(c) Determine the potential energy stored in the spring when the spring is unstretched.
J

Answer 1

The potential energy associated with a mass on a spring is a function of the amount that the spring is stretched or compressed from equilibrium.

E = 1/2 k x²

(a) 1/2 k x² where x = .0416 m
(b) 1/2 k x² where x = .0332 m
(c) 1/2 k x² where x = 0

Answer 2

The formula which gives the potential energy stored by a spring is
E=kyy/2. In the case of your problem
transform the strech in meters in order to obtain in case (a)
E=4.16x10^2x(4.16x10^-2)^2/2 joule
and your computer will do the rest.
Proceed in the same way in case (b)
In case (c) y=0 and so E=0.