Physics Help Please!!(7)?

Question

A 64.0 kg diver steps off a diving board and drops straight down into the water. The net force when in the water is an upward 1060 N. If the diver comes to rest 5.9 m below the water's surface, what is the total distance between the diving board and the diver's stopping point underwater?
m

Answer 1

Using conservation of energy, with the origin at the point where the diver stops in the water...

Work = Change in Energy

Initial energy ( diver steps off board ) = mgh
( 64 kg ) ( 9.8 m/s² ) ( h )

Final energy ( diver stopped in water ) = 0

Change in energy = work done by both water and gravity
( 1060 N - ( 64 kg ) ( 9.8 m/s² ) ) ( 5.9 m )

Put it all together and solve for h, the distance from the diving board to the stopping point.

Answer 2

Lets calculate the velocity diver hits the water
But first decelration in water
F=ma
-1060=64a
a=-16.5625 m/s²

V²=2as+U²
V=0
0=2(-16.5625)(5.9)+(U)²
U=13.97989626 m/s

Now lets caculate the distance trvelled by diver before hitting in the water .
V²=2as+U²
(13.97989626)²=2(9.8)(s)+(0)²
s=9.97130102 m

Total distance = 9.97130102 + 5.9
Total distance = 15.87130102 m