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f(x) = 1/4 ln (x^4)/ (1+x^4)

2007-12-14 01:16:48 · 2 answers · asked by Nicole 1 in Science & Mathematics Mathematics

2 answers

use the property of natural logarithm...

f(x) = (1/4) [4lnx - ln(1+x^4)]
= lnx - (1/4) ln(1+x^4)

thus
f'(x) = 1/x - (1/4)(1/(1+x^4))*(4x^3)
= 1/x - (x^3/(1+x^4))


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2007-12-14 01:38:54 · answer #1 · answered by Alam Ko Iyan 7 · 0 0

f (x) = ln x / (1 + x^4)
Using quotient rule:-
f `(x) = [(1 + x^4)(1 / x) - (ln x)(4x³)] / (1 + x^4)²

2007-12-14 12:07:17 · answer #2 · answered by Como 7 · 2 0

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