2007-12-13 17:50:59 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
In titration( the process of predicting the unknown concentration of a solution w/ a known concentration another solution) the formula would be , M of H2SO4 x Vol. H2SO4 = M of NaOH xVol. of NaOH, by Substitution 11.11ml. woul be the vol. for H2So4
2007-12-13 18:12:50 · answer #1 · answered by theCycle 1 · 0⤊ 0⤋
H2SO4+2NaOH---> SO4Na2+H2O
so you need 2 moles of NaOH for 1 H2SO4
1L of NaOH 0.2M contains 200mM of NaOH
25mL corresponds to 200*25/1000=5mM of NaOH
1L of 0.45M H2SO4 contains 450mM of H2SO4
1mL of 0.45M H2SO4 contains 0.450mM of H2SO4
to neutralize 5mM of NaOH , you need 2.5mM of H2SO4
and so you must use 2.5/0.45 =5.56mL of 0.45M H2SO4
2007-12-14 02:03:01 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
11.11ml
2007-12-14 02:01:23 · answer #3 · answered by newbie74cents 1 · 0⤊ 0⤋