I have been absent for a whole week and the teachers been teaching circular motion. I understand how to find the centripetal acceleration, but for some reason i can't find the period and dont even know the equation because the book doesnt have it!!!
the problem is
A motor 24 cm in diameter rotates at 2400 rpm.
a) find its period. <----- HELP ME!!! my english sucks T.T
b) find its centripetal acceleration
2007-12-13 14:24:04 · 4 answers · asked by jason j 1 in Science & Mathematics ➔ Physics
You are given an angular velocity of 2400 revolutions / minute. You desire to know the period, which is the time for one revolution. Period is the reciprical of angular velocity; in thic case, 1 minute / 2400 revolutions or 60 seconds / 2400 revolutions = 1 / 40 second / revolution.
Centripetal acceleration is v² / r or r ω² where v is the linear velocity at the rim and ω is the angular velocity.
2007-12-13 14:31:21 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
a) The period is the time it takes for 1 revolution, so it's the reciprocal of rpm. You probably want the period in terms of seconds, so
P = (1 min./2400 revs)(60 s/min)
P = (60 / 2400)s/rev
P = (1/40) s = 0.025 s
b) a = v^2 / r = rω^2
ω = 2π/P = 80π
a = 12(80π)^2 ≈ 757,985.6 cm/s^2 ≈ 7,580 m/s^2
2007-12-13 14:44:57 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
Given:
Diameter = 24 cm
RPM = 2400
Centripetal Acceleration: a = v² / r
Velocity in Meters Per Second = 9.6
Radus: 12 cm or 0.12 m
a = 92.16 / 0.12 = 768 m/s²
Period = 2π * Seconds Per Turn
Seconds Per Turn = 0.025
2π * Seconds Per Turn = 0.157
2007-12-13 14:54:15 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Its 2 AM and I cant do this I'm so exhausted IOU answers for A) and B) love you <3
2016-05-23 11:39:44 · answer #4 · answered by amada 3 · 0⤊ 0⤋