Deck= 52 cards
2007-12-13 14:15:01 · 17 answers · asked by twinkle 1 in Science & Mathematics ➔ Mathematics
1 in 26
2007-12-13 14:17:55 · answer #1 · answered by Jason 6 · 2⤊ 2⤋
The odds for the 1st Ace is 4/52 (4 Aces in a deck of 52). For the 2nd, it's 3/51 (3 Aces and 51 cards remaining).
So multiply 4/52 by 3/51 = 0.004524887
2007-12-13 22:20:28 · answer #2 · answered by Ron da Don 3 · 1⤊ 0⤋
221 to 1.
Explanation: The odds of the first card being an ace is 4 out of 52, or 1 out of 13. The odds of the second card being an ace is 3 (because one ace is already gone) out of 51 (because one card is already gone), or 1 out of 17.
your overall odds are 13 times 17 = 221 to 1.
2007-12-13 22:21:27 · answer #3 · answered by GIANTS_56 1 · 2⤊ 0⤋
4 out of 52
2007-12-13 22:18:04 · answer #4 · answered by Anonymous · 0⤊ 2⤋
1 ace in 1 draw = 4/52
2 ace in 2 draw = 4/52 x 3/52
4/52 x 4/52 x 3/52 = 0.0003
2007-12-13 22:20:55 · answer #5 · answered by ViewtifulJoe 4 · 1⤊ 2⤋
For the first one, you'll have:
52 cards and 4 possible aces, so
4/52 chance.
The second one, you'll have 51 cards left and only 3 aces, so
3/51
Then, to find the probability of getting both
P(AandB) = P(A) * P(B) <-- one of the most useful probability formulas you'll ever learn.
4/52 * 3/51 = 12 / 2601
2007-12-13 22:21:35 · answer #6 · answered by Useless Knowledge Goddess 4 · 0⤊ 1⤋
4/52+13/52-1/52=16/52
the answer is 16/52 or 8/26 or 4/13
2007-12-13 22:33:30 · answer #7 · answered by Kelly T 2 · 0⤊ 0⤋
4/52 * 3/51 = 12/2652 = 1/221 = .004524887 = 0.45%
2007-12-13 22:18:08 · answer #8 · answered by Zandia 3 · 2⤊ 0⤋
4/52 *3/51 = 1 out of 221.
Considering most of the answers here are wrong, do you really want to be asking math questions here?
2007-12-13 22:17:36 · answer #9 · answered by djt0704 2 · 2⤊ 0⤋
odds for FIRST card are 4/52. If you drew an ace, odds of SECOND card being an ace is 3/51. If you did not draw and ace on card one, odds of SECOND card being an ace is 4/51
2007-12-13 22:19:48 · answer #10 · answered by Mike 7 · 1⤊ 2⤋