2007-12-13 14:03:23 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
[04]
5(x-3)=10
x-3=2 [dividing both sides by 5]
x=2+3=5
2007-12-13 14:08:10 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
5(x-3)=10
5x - 15=10
5x = 10+15
= 25
x = 5
thats how to solve that ;)
2007-12-13 22:08:50 · answer #2 · answered by John J 1 · 0⤊ 0⤋
5(X-3) = 10
X-3 = 10/5
X-3 = 2
X = 2 + 3
X = 5
2007-12-13 22:10:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
multiply 5 with x and -3 =10
5x-15=10
5x=25
x=25/5
x=5
2007-12-14 03:19:04 · answer #4 · answered by C 3 · 0⤊ 0⤋
5(X-3)=10
Remove brackets by multiplying:
5X - 15 = 10
Transpose like terms:
5X = 10 + 15
5X = 25
X = 25/5
X = 5
2007-12-13 22:09:56 · answer #5 · answered by Robert S 7 · 0⤊ 0⤋
ok. To do this problem multiply both and and -3 by 5.
You then get the equation:
5x-15=10
Now add 15 to each side.
It should look like this:
5x=25
divide each side by 5:
5x/5=25/5
Here's your final answer.
x=5.
I hope you get how to do this now,
Sameer N.
2007-12-13 22:08:19 · answer #6 · answered by Sameer N 1 · 0⤊ 2⤋
5[x-3]=10
5[5-3]=10
5[2]=10
5*2=10
x=5
2007-12-13 22:11:43 · answer #7 · answered by adan s 2 · 0⤊ 0⤋
5(x-3)=10
5x-15=10
5x=25
x=25/5
x=5
2007-12-13 22:08:40 · answer #8 · answered by Megan 2 · 0⤊ 0⤋
what minus 3, time five equals 10?
2007-12-13 22:12:03 · answer #9 · answered by Mike Tyson 3 · 0⤊ 0⤋
You count your fingers, don't forget your toes, and then you agree with someone who gave the right answer.
2007-12-13 23:16:11 · answer #10 · answered by Anonymous · 0⤊ 0⤋