Probability Combinations?

Question

A piggy bank contains five "loonies" and eight "toonies." It is shaken until two coins drop out.

a) What is the probability that two loonies will fall out?

b) What is the probability that two toonies will fall out?

c) What is the probability that one of each type of coin will fall out?

Answer 1

ways to pick 2 loonies, 5C2 = 10
ways to pick 2 toonies, 8C2 = 28
ways to pick 2 coins out of 13, 13C2 = 78

P(2 loonies) = 10/78 = 5/39
P(2 toonies) = 28/78 = 14/39
P(1 of each) = (5•8)/78 = 20/39

Answer 2

hello again...lol

ok soo there are 5 "loonies" and 8 "toonies"
so there's a better chance that a toonie falls out right?
so in total there is 13 things

5/13= loonie= so it's a 38.5% chance 1 will fall out

5/26 = .192 so times it by 100 which= 19.2%so if its 2 it would be half of 38.5 which is

2 loonies= 19.2%

loonie= 5/13 which is 38.5% and toonie is 8/13 which is 61%

YOUR WELCOME

Answer 3

Assuming you are ignoring the factors of size and weight differences, you have 13 coins total.
Probability of first loonie
Prob(L)=#of loonies/total coins.=5/13
Probability of first twoonie
Prob(T)=#of twoonies/total coins=8/13
The probability of the second coin is dependent on what the first coin is.
If Loonie first, #of loonies is 4; #of twoonies is 8; Total coins is 12,
Prob(LL)=4/12=1/3
Prob(LT)=8/12=2/3

If Twoonie fist, # of loonies is 5; # of twoonies is 7; Total coins is 12
Prob(TL)=5/12
Prob(TT)=7/12

So answer for a):
Prob(L1 &L2)= Prob(L)*Prob(LL)
=5/13*1/3
=5/39

b)Prob(T1&T2)=Prob(T)*Prob(TT)
=8/13*7/12
=14/39

c)Prob(One of each)=Prob(LT) +Prob(TL)
=Prob(L)*Prob(LT)+Prob(T)*Prob(TL)
=5/13*2/3+8/13*5/12
=10/39+40/156
=10/39+10/39
=20/39

Answer 4

a) 5/13 * 4/12
b) 8/13 * 7/12
c) 1 - the answers to (a) and (b)
.

Answer 5

Probability of Success/Total Probability

a) C(5,2) / C(13,2)


b) C(8,2)/C(13,2)

c) C(5,1)xC(8,1)/C(13,2)

Answer 6

please mention whether all the loonies,toonies aer alike or distinct

if they are alike answers are

a)(5/13)*(4/12)
b)(8/13)*(7/12)
c)(8/13)*(5/12) or (5/13)*(7/12) both are correct

if they are distinct then

a)(5c2)/(13c2)
b)8c2/13c2
c)(5c1)*(8c1)/(13c2)

Answer 7

a)(5/13)*(4/12)
b)(8/13)*(7/12)
c)(8/13)*(5/12)