if i subject CH3-CH2-CH2-CH2-OH to dehydration, what will be the products???
2007-12-13 11:06:06 · 5 answers · asked by frizzy_ghost 1 in Science & Mathematics ➔ Chemistry
Dehydration of an alcohol such as 1-butanol produces a mixture of butenes: 1-butene, (CH2=CHCH2CH3) cis- and trans- 2-butene.
These are elimination reactions, and if you look at pages 10-37 to 10-47 on the link below it gives an excellent description.
2007-12-13 11:25:51 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You are starting with a primary alcohol. Lose OH from the end C and H to go with it from the next C; these make water. Add a bond if necessary to keep valencies correct. What you are left with is the other product.
Over to you!
2007-12-13 11:10:49 · answer #2 · answered by Facts Matter 7 · 0⤊ 0⤋
this is a type of elimination reaction
you will get H20 and an alkene....
1-butene ( CH3-CH2-CH=CH2 ) or
2-butene ( CH3-CH=CH-CH3 ) depending on your reaction conditions
2007-12-13 11:14:51 · answer #3 · answered by Anonymous · 1⤊ 0⤋
C2H5OH + H2SO4 = C2H2 +H2O CH3CH2OH + H2SO4 (dehydrator) --> H2C=CH2 + H2O there is no such chemical referred to as methene, considering you have basically one carbon to initiate with. so it fairly is impossible to get a double bond.
2016-11-03 04:40:17 · answer #4 · answered by ? 4 · 0⤊ 0⤋
when you have H2O out ,then It left C and you only can get C
2007-12-13 11:09:46 · answer #5 · answered by Anonymous · 0⤊ 2⤋