The equation is x/3 + 11 < 31. I haven't done these in a really long time and my brother needs help. I think I have the answer, but it doesn't plug in like it should. Thanks! I just need the answer and how to solve it.
2007-12-13 10:15:56 · 5 answers · asked by ♥TheBeatlesBiggestFan♥ 5 in Education & Reference ➔ Homework Help
As long as you only add or subtract or else you multiply or divide by only positive numbers, you can treat the ineqality like an equality.
So we can subtract 11 from both sides without changing anything:
x/3 < 20
And we can multiply both sides by 3 without changing anything
x < 60
Oops! I think we have an answer!
(Joythe's method also works, but she didn't subtract properly... 93 - 33 = 60; x < 60)
2007-12-13 10:22:06 · answer #1 · answered by dogsafire 7 · 0⤊ 0⤋
I would say the 2nd answer is right
This is how i would do it...
X/3 +11 = 31
X/3 = 31 - 11
X/3 = 20
X = 20 * 3
X= 60
Not sure if you are meaning < as an = sign
2007-12-13 10:28:52 · answer #2 · answered by soloespresso 1 · 0⤊ 0⤋
3(x/3) + 3(11) < 3(31)
x+33<93
+33<-33
x<63
2007-12-13 10:20:36 · answer #3 · answered by Joythe K 3 · 0⤊ 0⤋
5.7X+ninety six=8.2X+21 -ninety six -ninety six 5.7X =8.2X-75 -8.2X =-8.2X-75 -2.5X = -75 -2.5X/-75=-.03 (X could desire to = .03) my math is somewhat rusty, yet even if you do to one area of the = you do to the different, i may be somewhat incorrect on the subject of the final dividing step. i attempted to teach you what i did step via step. yet once you have a favorable you attempt and get all of it the way down to 0 (it somewhat is why i subtracted ninety six from ninety six) then did the same concept with X i'm hoping this helps a sprint!
2016-11-26 21:09:24 · answer #4 · answered by Anonymous · 0⤊ 0⤋
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
LOL differnent ansewers.
2007-12-13 10:23:31 · answer #5 · answered by Anonymous · 0⤊ 0⤋