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2007-12-13 04:30:19 · 5 answers · asked by ygolordned 1 in Science & Mathematics ➔ Physics
undetermined.
how is the bar attached to the wall ? any friction with wall and bar ?
2007-12-13 04:35:01 · answer #1 · answered by gjmb1960 7 · 0⤊ 1⤋
I don't believe that this is possible to workout without knowing the length of the rod (or the length of the cable, from which this length can be deduced), whether the fixed end of the bar acts a pivot and if the bar has a uniform mass- that is its centre of gravity is in the middle. With this information it is fairly easy to work out using torque of a couple and vector components equations.
2007-12-13 12:51:15 · answer #2 · answered by Anonymous · 0⤊ 1⤋
i make the answer 7.00N
find vertical component of tension in wire:
sin(30)x810 = 405N
i'm assuming force of bar is actualy weight of bar so to balance the forces the weight of the circle must be 405 = 398 + W
W = 405 - 398
= 7.00N
2007-12-13 12:58:52 · answer #3 · answered by pat_arab 3 · 0⤊ 2⤋
do we need the bar's length 2 solve this?
whts d answer anyway
2007-12-13 12:53:36 · answer #4 · answered by ear 2 · 0⤊ 1⤋
206 Newton
I assume it's MC question, so you can find this value among the choices.
2007-12-13 13:38:09 · answer #5 · answered by Alexander 6 · 0⤊ 1⤋