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I have been toiling over this for a while...*how* do you find the slope of a negative value for x in the graph of the parabola y = (1/100)x^2??

As an example, could you guys give me an explanation as to **how** you would get the answer for the point (-100, 100)???

2007-12-13 03:18:58 · 5 answers · asked by netsurfer733 2 in Science & Mathematics Mathematics

Awesome i got it, ty all :D

BUT! If someone can help with this...the second part of this problem requires me to find a point on the parabola in which its *tangent* line will intersect (50, 100)! Can anyone figure this out!?!?

2007-12-13 18:07:30 · update #1

5 answers

As has been said, the derivative dy/dx of x^n = nx^(n-1),
also, if a is a numeric constant, then
d(ay)/dx = (a)[da(y)/dx,
so d[(1/100)(x^2)/dx = (1/100)[d(x^2)/dx = (2)(1/100)x = x/50

The first derivative gives the slope at any point along the curve. So plug in whatever value of x to get the value of the slope at any particular point.

There are a number of derivatives you ought to know. This is one of them. And are a lot you'll become nauseatingly familiar through use. But, there are some reference books you can get that have just about everything you'll ever need to know in math (at least through your Bachelors degree)

A couple I use:
Mathematical Tables from Handbook of Chemistry and Physics, Tenth Edition; Hodgman, Selby, Weast; Chemical Rubber Publishing Co. Cleveland, OH, 1958

Stadard Mathematical Tables, Twelfth Edition; Selby; Chemical Rubber Publishing Co. Cleveland, OH, 1972.

Got the first when I was in College, and the second, I think I got that one because I couldn't find the first one.

2007-12-13 03:54:25 · answer #1 · answered by gugliamo00 7 · 0 0

The slope part has been answered. This is a parabola. To get the answer for -100,
dy/dx=2x/100=x/50 = -100/50=-2
and for x=100, x/50 = 100/50 = 2

2007-12-13 03:41:00 · answer #2 · answered by cidyah 7 · 0 0

slope of a function at a given point is the 1st derivative.
d(x²/100)/dx = 2x/100 = x/50
so when x = -100, slope is -2.

2007-12-13 03:24:18 · answer #3 · answered by Philo 7 · 0 0

You take the derivative:

dy = (2/100)x

Then supply the desired x:

dy(-100) = -2

2007-12-13 03:23:00 · answer #4 · answered by HooKooDooKu 6 · 0 0

dy/dx = 1/50x
At the point x = -100
dy/dx = -100/50 = -2

slope is -2

2007-12-13 03:22:01 · answer #5 · answered by r w 2 · 0 0

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