how to solve sin(300)?

Answer 1

sin(300°) = - sin (60°) = (- √3/2)

Answer 2

Calculator Answer: -0.866025

Non Calculator Answer: (√3)/2

Trigonometric Proof

sin(A+B)=sin A cos B + cos A sin B

sin(180+120)=Sin180cos120 + Cos180Sin120

Since
Sin180 = 0
Cos 180 = -1

Sin(300) = -Sin(120)

Use the rule again

-Sin(C+D) = sin C cos D + cos C sin D

-Sin(90+30) = (sin90 cos30 +cos90sin30)

Since
Sin(90) = 1
Cos(90) = 0
Sin(30) = 0.5
Cos(30) = sqrt(3)/2)

-Sin(120) = Cos30

Sin(120) = -sqrt(3)/2

Note: Most exams need you to remember the "standard" trig so it will be worth learning them, especially if you need to prove like above.

Hope this helps!!

Addition: Just noticed the quicker method below of 360-300. That will be better, but for future reference, there is the method above

Answer 3

sin(300) = +/- sin(360-300) = +/- sin(60)
To determine whether it is actually + or -, use this trick: All Students Take Calculus.
In the first quadrant, ALL functions are +.
In second, S(ine) is +.
In third, T(angent) is +.
In fourth, C(osine) is +.
Since 300 is in the fourth quadrant, and only cosine is + in that quadrant,
sin(300)= -sin(60) = -root(3)/2

Answer 4

sin(300)
=-sin(60) = -square_root(3)/2

Answer 5

Sin: -0.866025403784

Answer 6

sin(300 ) = -0.8660254038