2007-12-13 00:02:14 · 16 answers · asked by Nakshe 3 in Consumer Electronics ➔ Music & Music Players
ok,its really disgusting,everyone thinks its a wordplay.THEY ARE WRONG. If you get what she means by "all the boys wanna eat it", than fergalicious is what it taste like.If you dont knoe what eat it means than...... uuhhhhhhhh......heres the def........
. fergalicious
37 up, 59 down
A woman who's genetal secretions during sexual intercourse can be described as having a plesant taste. Generally not promiscuous.
"She's fergalicious! Boys line up around the block to eat her!"
2007-12-13 18:12:29 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Its a word that fergie made, she combined her name and delicious to make fergalicious, which personally I think is really stupid. In her music video, fergie refers to fergalicious as a type of candy/bubble gum, and uses it to describe herself. Yuck.
2007-12-13 00:06:33 · answer #2 · answered by Tina 2 · 0⤊ 0⤋
Shes's the F to the E R G the i the E and aint no other lady put it down like her she;s fergalicious
2007-12-13 00:05:01 · answer #3 · answered by kerriiixberriii 2 · 0⤊ 1⤋
It's a play on her name, Fergie. Instead of delicious, it becomes "fergalicious."
2016-05-23 08:51:09 · answer #4 · answered by ? 3 · 0⤊ 0⤋
it means Fergie is delicious. so she says fergalicious.
2007-12-13 00:04:43 · answer #5 · answered by jb 3 · 1⤊ 0⤋
Basically meaning that Fergi is HOT and Delicious!!
2007-12-13 00:05:17 · answer #6 · answered by Anonymous · 0⤊ 0⤋
It's a song that Fergie made up so it's just a cool word I guess
2007-12-13 00:03:55 · answer #7 · answered by dawn 5 · 0⤊ 0⤋
It means that the Black Eyed Peas have reached complete rock bottom.
2007-12-13 00:04:16 · answer #8 · answered by Flavor Vortex 7 · 0⤊ 0⤋
It is a combo of Fergie and delicious....cute but not in the Websters!
2007-12-13 00:05:21 · answer #9 · answered by Gone fishin' 7 · 0⤊ 0⤋
fergie is her name,
delicous is part of a cool word
fergie + delicious = fergilicious
2007-12-13 00:05:29 · answer #10 · answered by dragonbo0gie 1 · 0⤊ 0⤋