You should get a TI-89 or some other form of computer algebra system. They are great with integrals. And if you're not supposed to use technology, well, what do you think we're all doing?
2007-12-12 18:48:33
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answer #1
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answered by autumndaesy 2
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It might help to recognize that x^2 (sqrt(x) is the same as x^(5/2). You can use the same approach you've used in class for integrals of x^2, x^3, etc., but with this fractional exponent.
2007-12-12 18:53:12
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answer #2
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answered by nicholasm40 3
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take the antiderivative. of the function. then take the value of the antiderivative at x=2 and subtract that from the value of the antiderivative at x=4.
the easiest way to find the antiderivative is to use integration by parts.
2007-12-12 18:53:40
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answer #3
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answered by Anonymous
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query::sure indispensable of (x-4)/(x^2) from a million to 2 Now,(x-4)/(x^2) =x/x^2-4/x^2 =a million/x-4*(a million/x^2) So,? (x-4)/(x^2) dx =?(a million/x)dx-4?(a million/x^2)dx =lnx-4*(-a million/x)+C =lnx+4/x.+C returned sure indispensable of (x-4)/(x^2) from a million to 2 =ln2+2-ln1-4 = ln2-2 subsequently, U ARE marvelous.
2016-12-17 16:40:51
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answer #4
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answered by matheis 4
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If I read it right, the function is x ^ 2.5 ?
Now can you do it?
2007-12-12 18:54:51
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answer #5
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answered by roderick_young 7
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The answer is 33.338940428861497031310425773227
2007-12-12 19:09:56
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answer #6
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answered by Kenneth Koh 5
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