Triangle ABD’s BD is an opposite, AB is adjacent, AD is hypotenuse & angle ABD is 90 degree & AB = 6 cm. But in the line AD has point C & angle BCD is 90 degree. Show that CD = 6 (sec theta – cos theta).
How can I show this?
2007-12-12 18:12:04 · 3 answers · asked by f_line 1 in Science & Mathematics ➔ Mathematics
CD = AD -- AC = AB sec(A) -- ABcos(A) = 6(secθ -- cosθ)
where angle BAD = θ.
2007-12-12 18:36:56 · answer #1 · answered by sv 7 · 0⤊ 0⤋
Well, its late, so I will suggest this line:
I assume theta is angle DAB
To find BC, since ACB is a right triangle, it equals
6 sec (theta)
Now consider triangle DCB. Since angle ADB is one angle, the other angle that is NOT the right angle is also theta (angle CBD). Since we know BC, we can find CD.
2007-12-13 02:32:28 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
are we talking about two triangles?
2007-12-13 02:32:18 · answer #3 · answered by Just M 2 · 0⤊ 0⤋