could you tell me if this is correct. Are all the steps here for this problem ?
2x^2+4(3x-x^2)+3x
2x^2 + 12x - 4x^2 + 3x
-2x^2 + 15x
Did I leave out any steps
2007-12-12 16:20:15 · 10 answers · asked by Maggie L 1 in Science & Mathematics ➔ Mathematics
okay someone answered my question by saying everything was correct except it should be positive instead of negative .... does everyone agree ????
I have -2x^2 + 15x he said it should be
2x^2 + 15x that when you have anything squared its positive : /
2007-12-12 16:33:25 · update #1
Looks OK
You remove the brackets, then collect like terms.
Keep up the good work
2007-12-12 16:25:49 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Looks good to me.
2x^2+4(3x-x^2)+3x
2x^2 + 12x - 4x^2 + 3x (by expanding terms)
-2x^2 + 15x (by combining terms)
You might want to represent this as x(15-2x)
2007-12-12 16:25:52 · answer #2 · answered by MartinWeiss 6 · 1⤊ 0⤋
Yes, this is correct just that I am not sure what you are aiming at. The factors of the above equation would be x(15-2x).
I appreciate your work since you did try it instead of just asking it.
Good Luck.
2007-12-12 16:29:45 · answer #3 · answered by Anonymous · 1⤊ 0⤋
No, you have done all the steps... but it might be more help full in the future to tell us what you wanted. By that i mean, are just trying to add, subtract, or want to take derivative to this function... something like that.
you have done it right.
P.S npontello what has she done wrong... please give more details. I don't see any.
Also Yaman your wrong too... its not (a+b)^2 the only thing being squared is (3x - x^2) which means that her answer is right.
2007-12-12 16:25:25 · answer #4 · answered by Guts 3 · 0⤊ 1⤋
If all you are doing is simplifying then:
f(x) = 2x² + 4(3x - x²) + 3x
f(x) = 2x² + 12x - 4x² + 3x
f(x) = -2x² + 15x
f(x) = x(15 - 2x)
2007-12-12 16:30:27 · answer #5 · answered by Buffy S 3 · 1⤊ 0⤋
nope u are wrong
second step
(3x-x^2) = 3x + x^2 because anything squared is always positive
so just fix that
2007-12-12 16:26:27 · answer #6 · answered by Yaman 1 · 0⤊ 2⤋
You are perfectly correct!
2007-12-12 16:28:17 · answer #7 · answered by Anonymous · 1⤊ 0⤋
No,you didn't leave out any steps.(^_^)
2007-12-12 16:28:25 · answer #8 · answered by An ESL Learner 7 · 1⤊ 0⤋
nope.. you did not.. it's absolutely correct!! keep it up!! :)
2007-12-12 16:34:53 · answer #9 · answered by jvc^_^ 1 · 1⤊ 0⤋
Nope :]
2007-12-12 16:23:24 · answer #10 · answered by npontello12 2 · 0⤊ 0⤋