What would the dimensions of a square be if the area is 56?

3 ⤊

2007-12-12 15:58:46 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

Let side length = x
x² = 56
x = √56
x = √(4 x 14)
x = 2√14

2007-12-12 21:40:54 · answer #1 · answered by Como 7 · 3⤊ 0⤋

Area = length x width
This is a square so length = width
So, Area = lengthÂ²
56 = lengthÂ²
sqrt(56) = length
length = 7.48

Square is 7.48 x 7.48

2007-12-13 00:06:12 · answer #2 · answered by Buffy S 3 · 0⤊ 0⤋

56=x^2
sqrt56=x
x=2sqrt14

2007-12-13 00:01:39 · answer #3 · answered by catsfanj 3 · 0⤊ 0⤋

sqt(56) = 7.48

7.21^2 = 55.95 = 56

2007-12-13 00:08:39 · answer #4 · answered by dark_x2000 2 · 0⤊ 0⤋

each side is sqrt(56) = 2sqrt(14)

2007-12-13 00:01:36 · answer #5 · answered by MartinWeiss 6 · 0⤊ 0⤋