Algebra 2 homework help! plz?

Question

1. f(x) =(x^2-9)(x+2)^-3
[the ^ means the number following it is an exponent, idk how to do that lol.]
if you could show me how to set it up that would help alot thanks

Answer 1

What do you mean by "set it up?" What do you want to do?

Because your second term has the negative exponent, you can rewrite your function as:

f(x)=(x^2 - 9)/(x+2)^3

You can also factor the numerator and say:

f(x)=((x+3)(x-3))/(x+2)^3

From here, you can tell, the domain of this function is all real numbers EXCEPT for x=-2. You have zeros at +3 and -3.

What else do you want to know??

Answer 2

hey i havent had alg. 2 since last year but i know that (x^2-9) is a special case and it equals (x+3)(x-3)... if that helps at all. and i think you set the whole equation equal to zero. then maybe you distribute the -3 exponent to x and 2 then you use zero product property(set each one equal to zero and solve for x) and no im really not a nerd. im just doin precal now too.