If the length is a randomly chosen integral number of meters, what is the expected area of this enclosure?
2007-12-12 13:20:17 · 3 answers · asked by futuramakif 2 in Science & Mathematics ➔ Mathematics
If the length is a randomly chosen integral number of meters, what is the expected area of this enclosure?
Sorry, yes the total amount of fencing used is 36m (i believe that means it is the perimeter) and it is a rectangle with one side being a randomly chosen integral number.
2007-12-12 13:29:58 · update #1
A complete solution would be greatly appreciated.
2007-12-12 13:31:07 · update #2
You need to explain your question more properly. Do you mean if the length of the total fencing, or are we to assume that the area he will enclose is a rectangle, and one side of the rectangle will have a length of a random integer.
If that is assumed, then two sides of the rectangle are x, and the other two sides are 18-x, so if you just multiply those two dimensions together, you'll find that the area of the rectangle is 18x-x^2
2007-12-12 13:25:38 · answer #1 · answered by nerdofwrath 2 · 0⤊ 0⤋
Half of 36m is 18m, so let's say a 10 x 8 rectangle of 80 sm.
Or a 9 x 9 square would be 81 sm. You need to be precise.
2007-12-12 13:26:08 · answer #2 · answered by Robert S 7 · 0⤊ 0⤋
57m²
Add up the areas for all the possible lengths = 969
17 possible lengths
Expected area = 969 / 17 = 57
2007-12-12 13:28:22 · answer #3 · answered by steele 6 · 0⤊ 0⤋