A 0.309-g sample of coal is burned in a bomb calorimeter ....?

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A 0.309-g sample of coal is burned in a bomb calorimeter ....?

A 0.309-g sample of coal is burned in a bomb calorimeter with a heat capacity of 4.62 kJ/oC. The temperature in the calorimeter rises from 20.45oC to 22.28oC. Calculate the heat of combustion of the coal in kJ/g.

trying to finish a study guide ughh.

2007-12-12 13:02:24 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

1 answers

q=CdeltaT

q= 4.62 x (22.28-20.45)

q= 8.4546 kJ

in this reaction 8.4546 kJ of heat were produced so how much heat is produced per gram? Since the reaction occurred with 0.309-g then we must divide 8.4546 by that

8.4546 kJ / 0.309-g = 27.4 kJ / g

2007-12-16 09:51:35 · answer #1 · answered by Mr. T 2 · 0⤊ 0⤋