2007-12-12 12:24:56 · 5 answers · asked by Mishelle B 1 in Science & Mathematics ➔ Mathematics
Huh?
I'm going to have to try and put my "psychic" hat on to guess what your full question is. Do you mean what is the maximum area for a quadrilateral with a perimeter of 44 cm?
The shape with the maximum area would be a square, each side with a length of x.
Four sides equal 44 cm:
4x = 44
x = 11
So each side is 11 cm.
The area of the square would be x²
x² = 121
Maximum area of a quadrilateral with perimeter 44 cm is a square with an area of 121 sq. cm.
How did I do with my "psychic" abilities?
2007-12-12 12:28:58 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
This is a stupid question.
Maybe you want to optimize the area when having 44 centimeters of a certain thing to form the area. To do that, we need a function that describes the dimensions of the figure, then use the first derivative to find maximum values.
2007-12-12 20:32:54 · answer #2 · answered by JDickens10 2 · 0⤊ 0⤋
44 x 44
2007-12-12 20:27:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Is that the perimeter of a shape?
Do you want to find a geometrical shape of perimeter 44cm that maximizes the area ?
I assume it is a perimeter of a circle
P = 2Pi R= 44
R = 44/(6.28) =7 cm
Area of a circle with radius =7 is
A = Pi R^2 =3.14 * 7^2=153.86 cm^2
A circle is the best plane shape that maximizes a given perimter.
2007-12-12 20:31:29 · answer #4 · answered by Any day 6 · 0⤊ 0⤋
maximum area (for perimeter 44cm) = {44cm/4}^2 = 121 cm^2
2007-12-12 20:33:17 · answer #5 · answered by sv 7 · 0⤊ 0⤋