OMG MATH HELp!!!?

Question

Use linear combinations to solve the linear system
2v=150-1u
2u=150-1v

Answer 1

Solve one of the equations in terms of just v:
2v = 150 - u
v = (150 - u)/2

Now substitute this into the second equation for v:

2u = 150 - (150-u)/2

Multiply both sides by 2 to get rid of the fraction:
4u = 300 - (150 - u)
4u = 300 - 150 + u
4u = 150 + u
3u = 150
u = 50

Now solve for v:
v = (150 - u)/2
v = (150 - 50)/2
v = 100 / 2
v = 50

Cool! u = 50, v = 50

Answer 2

first move the v and u terms to the left of the = by adding the opposite of the ones on the right, and wrote them so they line up under each other. You'll get
1u + 2v = 150
2u + 1v = 150

Then multiply the top by -2 and leave the bottom alone
-2u -4v = -300
2u + 1v = 150

Then add the rows
-3v = -150 and divide by -3 to get v = 50

Then plug that in to either equation to get u

Answer 3

u = 150 - 2v

2(150 - 2v) = 150 - v

300 - 4v = 150 - v

150 = 3v

v = 50

u = 150 - 2v = 150 - 2(50) = 50

Therefore,
u = 50 and
v = 50

Answer 4

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