Algebra 1 problems hw help plz.?

Question

it says factor.

-2(m+3)-(m-2)
do you distribute? is 2 positive???
is it times -1 (m-2) or + -m-2

5m^3-20m^2+25m
(GCF is 5m right?, then how do you factor the trinomial?)

(x+4)^2 - x^2
(after distribute, does the x^2 cancel out?)

5m(m² - 4m + 5)


can the trinomial ( )
be factored too?
by what? or is it already factored as it ???

Answer 1

PROBLEM 1:

You can distribute the -2 through the first parentheses:
-2m - 6 - (m-2)

You can also distribute the minus sign (-1) through the second parentheses:
-2m - 6 - m + 2

Then combine everything back together:
-3m - 4

PROBLEM 2:
Yes, 5m is the GCF of the 3 terms:

5m(m² - 4m + 5)

You can then factor the stuff in parentheses:
5m(m - 5)(m + 1)

PROBLEM 3:

Yes, after distributing the x² will cancel:

(x² + 8x + 16) - x²
= 8x + 16
= 8(x + 2)

Answer 2

Each term inside the parenthesis is multiplied by the term outside. A number is always positive unless it is preceded by minus: -2 is the same as -1*2 and -(m-2) = -1*(m-2). Multiplying out the first equation: -2m-6-m+2 = -m-4 = -(m+4)

Right: 5m(m^2-4m+5) now you can use the binomial theorem to factor.

Yes because a square is always positive.

Answer 3

For single variable problems, just get the variable all on side and isolate it completely. 1. Subtract 1/2 Y from both sides so you have a positive value as a coefficent-number next to variable- (this isn't necessary; just more convenient) Then isolate it by adding 4 to both sides to get it off the left. Finally divide both sides by 1/4 Y (that's what's left) and you have your answer. 2. Multiply the values into the parentheses and do the same. Make sure you watch the negative signs. You need to multiple -4 into (X+1). 3. Same type as the first. Sorry I'm not giving you answers but that won't help in the long run. Try asking a smart friend if this doesn't help but there are several math sites that can give you in depth help for this general type of problem. Look for Single variable equations I think.

Answer 4

1) -2(m+3)-(m-2)
-2m-6-m+2
-3m-4

2)5m^3-20m^2+25m
5m(m^2-4m+5)

3) (x+4)^2-x^2
x^2+8x+16-x^2
8x+16
8(x+2)

Answer 5

--2(m + 3) -- (m -- 2) = --2m --6 --m + 2 = --3m --4

5m^3 -- 20m^2 + 25m = 5m(m^2 --4m +5)

(x+4)^2 --x^2 = (x+4+x)(x+4--x) = 4(2x+4) = 8x + 16

Answer 6

-2(m3) start
-2m + 6

-2(m-2) other side
-2m - 4

(-2m +6)-(-2m - 4)
-4m + 2

Answer 7

-2m-6-m+2 which is -3m-4

GCF is 5m

x^2+4x+4x+16-x^2 = 8x+16

Answer 8

a) -2(m+3)-(m-2) answer -2m-6-m+2=-2m-m-6-2=m+4

Answer 9

-3m-4