Factor out 36x^5 - 64x^3y^2 using Differnce of Squares, Perfect Squares, etc... (Algebra 1 Expierience).?

0 ⤊

Factor out 36x^5 - 64x^3y^2 using Differnce of Squares, Perfect Squares, etc... (Algebra 1 Expierience).?

2007-12-12 11:28:03 · 2 answers · asked by Ichabod 1 in Science & Mathematics ➔ Mathematics

2 answers

36x^5-64x^3y^2

4x^3(9x^2-16y^2)
4x^3(3x-4y)(3x+4y)

2007-12-12 11:32:45 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋

Simplifying
36x^5 + -64x^3y^2

Reorder the terms:
-64x^3y^2 + 36x^5

Factor out the Greatest Common Factor (GCF), '4x3'.
4x^3(-16y^2 + 9x^2)

Factor a difference between two squares.
4x^3((4y + 3x)(-4y + 3x))

Final result:
4x^3(4y + 3x)(-4y + 3x)

2007-12-12 11:55:01 · answer #2 · answered by mathdummie11 2 · 0⤊ 0⤋