2007-12-12 11:10:54 · 4 answers · asked by Ichabod 1 in Science & Mathematics ➔ Mathematics
use the difference of two squares...
(x^4 - y^4)(x^4+y^4)
(X^2 - y^2) (x^2+y^2)(x^4+y^4)
(x+y)(x-y)(x^2+y^2)(x^4+y^4)
2007-12-12 11:14:39 · answer #1 · answered by jamesyoy02 6 · 0⤊ 0⤋
Simplifying
x^8 + -1y^8
Factor a difference between two squares.
(x^4 + y^4)(x4 + -1y^4)
Factor a difference between two squares.
(x^4 + y^4)((x^2 + y^2)(x^2 + -1y^2))
Factor a difference between two squares.
(x^4 + y^4)((x^2 + y^2)((x + y)(x + -1y)))
Final result:
(x^4 + y^4)(x^2 + y^2)(x + y)(x + -1y)
2007-12-12 12:00:43 · answer #2 · answered by mathdummie11 2 · 0⤊ 0⤋
Simplifying 36x^5 + -64x^3y^2 Reorder the words: -64x^3y^2 + 36x^5 element out the suited ordinary element (GCF), '4x3'. 4x^3(-16y^2 + 9x^2) element a distinction between 2 squares. 4x^3((4y + 3x)(-4y + 3x)) very end result: 4x^3(4y + 3x)(-4y + 3x)
2016-12-17 16:17:49 · answer #3 · answered by russ 4 · 0⤊ 0⤋
x^8-y^8=
(x^4-y^4)(x^4+y^4)=
(x^2-y^2)(x^2+y^2)(x^4+y^4)
(x-y)(x+y)(x^2+y^2)(x^4+y^4)
2007-12-12 11:30:25 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋