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I'm taking Geometry, and I probably learned this in Algebra, but I forget how to solve a two-variable equation!
Such as:
5x-1=3y
or
2y+1=2x+3
Please explain, don't just do the problem, because I have many more problems to do on my own!

2007-12-12 10:59:20 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

If you have a single equation, like 5x - 1 = 3y, you can solve for one of the variables.

EXAMPLE 1:

5x - 1 = 3y

Divide both sides by 3:
(5x - 1) / 3 = y

y = (5x - 1)/3

Distribute the 3 through the parentheses:
y = (5/3)x - 1/3

There's your equation in terms of y.

EXAMPLE 2:

2y + 1 = 2x + 3

Subtract 1 from both sides:
2y = 2x + 3 - 1
2y = 2x + 2

Divide both sides by 2:
y = x + 1

Again, you have now written the equation in terms of y.

2007-12-12 11:04:53 · answer #1 · answered by Puzzling 7 · 0 0

Put into the form with y on the LHS and x on the right:
3y = 5x - 1
y = (5/3)x - 1/3
or 2y = 2x + 3 -1 = 2x + 2 = 2(x+1)
y = x + 1
y is the function of x.
Now if you have both eqns existing at the same time, then you can solve simultaneously to find both variables.
I really hope that this helps.

2007-12-12 11:04:48 · answer #2 · answered by kellenraid 6 · 0 0

i exploit substitution x- 2y=a million x+y = 4 so i remedy the 2d equation for y y = x-4 now u replace this, anyplace there is y interior the 1st equation x -2 (x-4) = a million x - 2x + 8 = a million -3x = -9 x = 3 you have got here across x, and now u replace it in any equation to locate y 3 + y = 4 y = 4 - 3 y = a million :) x

2016-12-17 16:17:09 · answer #3 · answered by russ 4 · 0 0

5x-1=3y
5x-1+1=3y+1 isolate the variable
5x=3y+1
5x/5=3y+1/5 divide both sides by number w/ variable
x=3y+1 x equals 3y plus 1 over five
5

2007-12-12 11:07:05 · answer #4 · answered by So totally AWESOME its not funny 3 · 0 0

2y+1=2x+3

2y = 2x +3 -1 = 2x +2
y = x +1
line of slope =1 and y intercept =1

examples like this are equations of a line.

you graph the line and any ordered pairs that are on the line are solutions of the equation.

2007-12-12 11:06:58 · answer #5 · answered by Anonymous · 0 0

either use can use the substituion or elimination method..just remember in a two variable equation, there should always be two equations to be solvable....otherwise use have to use iteration methos (gauss-jordan method)

2007-12-12 11:03:55 · answer #6 · answered by jamesyoy02 6 · 0 0

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