there are nine side dishes. mary wants three different sides. how many combinations can she make? how do you solve this is it "9!"?
also...mary wants 2 out of 9 sides and 1 out of 3 main dishes. how many combinations are possible?
2007-12-12 10:25:04 · 8 answers · asked by xpopxprincessx9x 2 in Science & Mathematics ➔ Mathematics
Well the other answer is surely wrong. How many sub sets are there when you have 10 items and need to have 3 items in a subset? Think about it.
2007-12-12 10:30:17 · answer #1 · answered by . 6 · 0⤊ 0⤋
9 x 8 x 7 choices or 9! - 6!
9 x 8 x 3 choices or 9! - 7! + 3! - 2!
2007-12-12 10:30:33 · answer #2 · answered by Robert S 7 · 0⤊ 0⤋
9-6 = 3.
9-2-4 = 3.
9-5-1 = 3
9-2-3-1 = 3
2007-12-12 10:33:15 · answer #3 · answered by oumar_coulibaly2003 1 · 0⤊ 0⤋
Mary needs to go on a diet
2007-12-12 10:32:25 · answer #4 · answered by bonita 2 · 0⤊ 0⤋
do
it
yourself
i just got 2 points=]
2007-12-12 10:28:55 · answer #5 · answered by sammi a 2 · 0⤊ 0⤋
3 i think!
2007-12-12 10:27:56 · answer #6 · answered by Anonymous · 0⤊ 0⤋
27 u multiply 9 by 3 and the 2nd idk
2007-12-12 10:29:32 · answer #7 · answered by Anonymous · 0⤊ 0⤋
3;2;1.
2007-12-12 10:39:15 · answer #8 · answered by Anonymous · 0⤊ 0⤋