27^radical 5 x 9^ radical 5
I sort of know what to do but not sure. I know how to solve though.
2007-12-12 09:57:27 · 7 answers · asked by Ballerina 5 in Science & Mathematics ➔ Mathematics
way radical, like.
2007-12-12 10:01:23 · answer #1 · answered by clavdivs 4 · 0⤊ 0⤋
27√5 X 9√5 =
3^3√5 X 3^2√5 =
3^5√5
2007-12-12 10:05:46 · answer #2 · answered by Joe L 5 · 0⤊ 0⤋
27 radical 5 * 9 radical=243 radical 5
2007-12-12 10:03:58 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
27^radical 5 x 9^ radical 5
27^rt(5)*9^rt(5)
[27*9]^rt(5)
[{3}^3*{3}^2]^rt(5)
[{3}^5]^rt(5)
3
(x^a)^rt(a)=x
using this above only we get 3
2007-12-12 10:07:12 · answer #4 · answered by Siva 5 · 0⤊ 0⤋
27^(sqrt(5)) * 9^(sqrt(5))
27 = 3^3
9 = 3^2
27^(sqrt(5)) = (3^3)^(sqrt(5)) = 3^(3 sqrt(5))
9^(sqrt(5)) = (3^2)^(sqrt(5)) = 3^(2 sqrt(5))
27^(sqrt(5)) * 9^(sqrt(5)) = 3^(3 sqrt(5)) 3^(2 sqrt(5))
= 3^(3 sqrt(5) + 2 sqrt(5))
= 3^(5 sqrt(5))
2007-12-12 10:06:09 · answer #5 · answered by PeterT 5 · 0⤊ 0⤋
27^(sqrt(5)) * 9^(sqrt(5))
27 = 3^3
9 = 3^2
27^(sqrt(5)) = (3^3)^(sqrt(5)) = 3^(3 sqrt(5))
9^(sqrt(5)) = (3^2)^(sqrt(5)) = 3^(2 sqrt(5))
2007-12-12 10:10:54 · answer #6 · answered by J 6 · 0⤊ 0⤋
-630
2016-04-08 23:30:05 · answer #7 · answered by Anonymous · 0⤊ 0⤋