Two math questions I need help on please?

Question

1. Given the ratios of the lengths of the sides of triangle DEF and triangle XYZ. Is triangle DEF similar to triangle XYZ?
Triangle DEF 1:1:2
Triangle XYZ 3:3:6

A)Yes
B)No
C)Cannot be determined


2. Solve the following proportion
3/y + 2 = 2/y

A)4
B)1
C)3
D)2

Answer 1

PROBLEM 1:

Actually, neither one of them would be a triangle because sides of 1:1:2 (or 3:3:6) would make a straight line*.

(*The rule for triangles is that the two shorter sides must always add up to more than the longer side. 1 + 1 is *not* greater than 2 and 3 + 3 is *not* greater than 6.)

However, generally if all the sides have the same multiplier, they would be similar. For example triangles with ratios 3:4:5 and 9:12:15 would be similar because every side is 3 times as big as the first triangle.

The intended answer was A, but please tell your teacher that these aren't triangles.

PROBLEM 2:

I assume y + 2 is in the denominator:

.. 3 .... 2
------- = ---
y + 2 .. y

Cross multiply:
3y = 2(y + 2)

Distribute the 2 through the parentheses:
3y = 2y + 4

Subtract 2y from both sides:
y = 4

Answer:
A) 4

Answer 2

1- neither 1:1:2 and 3:3:6 would make a straight line. Although since sides have the same multiplier, they would be similar. So it should be A, but it's not triangles
2-
3/(y + 2) = 2/y
3y = 2(y + 2)
3y = 2y + 4
y = 4

So it's A

Answer 3

1) yes because the ratio is similar
2) A 3/6 = 2/4