Math questions, please help!!?

Question

can someone help me with these math problems??

x^2 + x + 5 = 0

x^2 + 4x +1 = 0

Please help me start them off!! thanks

Answer 1

use the quad formula x = (-b +/- sqrt(b^2 - 4ac) )/ 2a

a = 1,b=1,c=5

x= (-1 +/- sqrt(1 - 4*1*5))/2
= -1/2 +/- sqrt(-19)/2
= -1/2 +/- dwrt(19)/2 i (or no real sol)

a=1, b=4, c=1
x=(-4 +/- sqrt(16-4*1*1))/2
= -2 +/- sqrt(12)/2
= -2 +/- sqrt(3)

Answer 2

Either quadratic formula or completing the square

For ax^2 + bx + c = 0

x = [-b + sqrt (b^2-4ac)] / (2a) and [-b - sqrt (b^2-4ac)] / (2a)

For completing the square:

x^2 + x = 5
x^2 + x + 1/4 = 5 + 1/4
(x + 1/2)^2 = 5.25
x + 1/2 = +/- sqrt(5.25)
x = -1/2 + sqrt (5.25) and -1/2 - sqrt(5.25)

x^2 + 4x = 1
x^2 + 4x +4 = 1 + 4
(x + 2)^2 = 5
x + 2 = +/- sqrt(5)
x = -2 + sqrt(5) and -2 - sqrt(5)

Answer 3

use the quadratic fomula on these becuase they are not factorable.

if your quadratic function is in the form of:
ax^2 + bx + c = 0

then plug a,b and c into the quadratic equation:
[-b (+-) sqrt(b^2 - 4ac)] / (2a)


definition:
(+-) = plus or minus
sqrt() = square root function

Answer 4

x*x +x = -5
X(x+1) = -5

Answer 5

you need to use the quadractic formula:


thats too hard to type out on here....but i assume you should know what that is!