Simplify Complex Numbers? Help?

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How do I simplify this:

i^3(4-3i)

Show in steps and explain. Thanks!

2007-12-12 08:39:16 · 2 answers · asked by cgarletts 1 in Science & Mathematics ➔ Mathematics

First distribute:
(i^3)*4 - (i^3)*(3*i)

Regroup:
4*i^3 - 3*i^4

Recall that i^2 = -1:
4*i*(-1) - 3*(-1)*(-1)
-4*i - 3
-3 - 4*i

2007-12-12 08:46:56 · answer #1 · answered by lithiumdeuteride 7 · 0⤊ 0⤋

distribute
4i^3-3i^4
since i=sqrt(-1), i^2=-1 and i^3=(i^2)(i)
i^3=(-1)i
i^4=(i^2)(i^2)=(-1)(-1)=1
-4i-3

2007-12-12 16:48:23 · answer #2 · answered by Matt G 2 · 0⤊ 0⤋