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x,y and z represent lengths
a) x+y
b) xy
c) xy/z
d) x/y+z
Could some please explain this to me? I'm not sure on this dimensional analysis, I got: length, area, volume and area
Thanks

2007-12-12 08:26:01 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

a) x+y you are adding lengths, so this is length

b) xy you are multiplying a measure of length, e.g., cm, by itself, so units are cm^2. What does this measure

c) xy/z

do this: cm*cm/cm, cancel, what do you have?

d) x/y+z

do as in (c) (cm/cm) + cm =
dimensionless constant + cm

this is length, plus a constant.

2007-12-12 08:28:30 · answer #1 · answered by Anonymous · 2 0

Since you are not using any particular units of length, let
length be represented by L units.

So you have x L, y L and z L. That might well look a bit strange but if L were in metres it would be x m, y m and z m.
Now, perform a dimensional analysis on each of a) to d).

a) x+y is L + L which is still L, so x + y is a length.

b) xy is L x L which is L^2, so xy is an area.

c) xy/z is (L x L)/L which is L^2/L which is L, so xy/z is a length.

d) x/y + z, if this is (x/y) + z then you have (L/L) + L which is L so (x/y) + z is a length.

If x/y + z is x/(y+z) then you have L/L which has no dimensions.

2007-12-13 02:29:13 · answer #2 · answered by Anonymous · 0 0

the two first lines is measured in length units, for instance m.

The third line give you a length too because you divide the m^2 with m and then get m.

x/y +z is a relationship summed with length. Nonsense!

2007-12-12 09:25:33 · answer #3 · answered by anordtug 6 · 0 0

a) addition of lengths gives a length
b) product of lengths gives a surface (or area)
c) surface per length gives a length
d) addition of a constant with a length, this is not a correct calculation if you consider dimensions

2007-12-12 09:03:25 · answer #4 · answered by Anonymous · 0 0

a length
b area
c volume
d length

I've guessed the last 2.
Good luck.
Hope you get better answers than this.

2007-12-12 08:31:14 · answer #5 · answered by Anonymous · 0 0

2rh AREA π + 4h NONE (r+h)^2 divided by 3b LENGTH b^3 + rh NONE π^2(h+r) LENGTH bhr divided by (b+h)AREA

2016-05-23 06:35:18 · answer #6 · answered by ? 3 · 0 0

have u tried the site n looking 4 the mark scheme
it's from a AQA paper coz i remeber doing it last year

2007-12-14 03:48:26 · answer #7 · answered by angel2cool 3 · 0 0

a) length
b) length X length =length squared= area
c) length squared/length=length
d)length

2007-12-12 11:03:39 · answer #8 · answered by Anonymous · 0 0

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