How many moles of solute particles are present in 1 L of each of the following aqueous solutions?
(a) 0.4 M KI
mol
(b) 0.090 M HNO3
mol
(c) 10-4 M K2SO4
mol
(d) 0.07 M ethanol (C2H5OH)
2007-12-12 07:58:56 · 5 answers · asked by cntrstrk132 1 in Science & Mathematics ➔ Chemistry
Molarity (M) is a unit of concentration measured in moles per 1 Liter of solution, M=(mol/1 L). So, if you have 0.4M solution of KI, then you can set it up as follows, with X equalling the number of moles of solute:
0.4M=(X/1L), which is the same as saying
0.4 mol/L=(X/1L)
When you multiply both sides by 1 L you are left with X=0.4mol.
Likewise, (b) would be 0.090 mol, (c) would be 10-4 mol, (d) would come out to 0.07mol.
2007-12-12 08:06:09 · answer #1 · answered by Alli 3 · 0⤊ 0⤋
Multiply each molarity by 1, and that is equal to the moles.
Molarity = Moles of Solute / Liters of solution
So if you have a .4 molarity solution that means you have .4 moles of solute, for every one liter.
The same goes for the rest of them. .09 M solution is .09 moles for every one liter.
2007-12-12 08:03:31 · answer #2 · answered by ovenmits1 2 · 0⤊ 0⤋
For each compound figure out into what ions (if any) it splits when you dissolve it in water. Multiply the number of ions it splits in with the molarity that is given and you're done! If it doesn't split, the molarity that is given is your answer.
2007-12-12 08:06:03 · answer #3 · answered by ChatNoir 4 · 0⤊ 0⤋
a) 0.4 moles per litre
b) 0.09 moles per litre
c) 10^-4 moles per litre
d) 0.07 moles per litre
NB the large case 'M' means moles contained in one litre(dm^3)
2007-12-12 08:05:25 · answer #4 · answered by lenpol7 7 · 0⤊ 0⤋
are you in mr. simons honors/college chemietry class?
2007-12-13 15:36:52 · answer #5 · answered by Anonymous · 0⤊ 0⤋