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Partially correct. When one is talking about the bond itself, it means the difference in electronegativities between the two atoms of the bond. CH4 is nonpolar because the electronegativity of carbon (2.55) and hydrogen (2.2) are very close. But, when we're talking about CF4, the electronegativity of fluorine is 4.0, while carbon is 2.55. This means that fluorine has a huge amount of pull on the electrons from carbon, making the electrons more likely to be around fluorine rather than carbon, producing a polar covalent bond. BUT, the actual entire molecule of CF4 itself is nonpolar, as is methane. The reason for that is that every CF polar bond is pointing in a certain angle along a tetrahedral structure typical of CF4 and CH4, in such a way that all the polar bonds cancel in each direction. If you think of each bond as a vector, the vector sum is equal to zero, so the CF4 MOLECULE is nonpolar, but the INDIVIDUAL CF bonds are polar. CH4 bonds are simply inherently nonpolar, but both CF4 and CH4 are nonpolar molecules.

2007-12-12 07:38:19 · answer #1 · answered by Bryan L 2 · 5 0

Cf4 Polar

2016-11-09 03:23:34 · answer #2 · answered by Anonymous · 0 0

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Where's your chemistry book, hon? This is a page of answers. hint: double bonds are virtually never polar, symetrical configurations are never polar, mono atomic compounds are never polar, the further apart the elements are (left and right) on the periodic table, the more likely they are to form polar molecules

2016-04-01 06:47:05 · answer #3 · answered by ? 4 · 0 0

Because F is more electronegative then C, so it will pull Carbon's electrons towards itself, now imagine you have the CF4 molecule, each F is pulling on the carbon from each side, so that means that since everything is symmetrical, the pulling cancel each other out

2007-12-12 07:52:44 · answer #4 · answered by Answer 7 · 1 0

The bond is a lot more polar because F is a lot more electronegative than C.

The molecule as a whole, however, is still non-polar because the individual bond dipoles cancel out.

2007-12-12 07:36:26 · answer #5 · answered by Facts Matter 7 · 2 1

The electronegativity difference between carbon and fluorine is higher than between carbon and hydrogen. So the bond between C and F is polar.

2007-12-12 07:46:15 · answer #6 · answered by Shekhar h591 1 · 2 0

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