√49z^28 / 9
a. 49z^14 / 9
b. 7z^14 / 9
c. 7z^14 / 3
d. 7z^26 / 3
2007-12-12 07:28:31 · 7 answers · asked by . 1 in Science & Mathematics ➔ Mathematics
answer is C
√49 = 7
√z^28 = z^14
√ 9 = 3
2007-12-12 07:32:07 · answer #1 · answered by David F 5 · 0⤊ 0⤋
I'll assume that the square root encompassed all numbers:
sqrt(49z^28 / 9)
= sqrt(49/9)sqrt(z^28)
= (7/3)*z^14
= 7z^14/3 so c
When taking square roots of variables we just need to take half of the exponent - with numbers we just either use a calculator or recognize the number as a perfect square and proceed as such.
Hope this helps!
2007-12-12 07:32:24 · answer #2 · answered by highschoolmathpreparation 3 · 0⤊ 0⤋
Take the square root of each factor under the radical.
sqrt (49) = 7
sqrt (z^28) = z^14
sqrt (1/9) = 1/3
â49z^28 / 9 = 7z^14 / 3
2007-12-12 07:34:20 · answer #3 · answered by Hiker 4 · 0⤊ 0⤋
I think this is:
=â(49z^28 / 9)
=â(49z^28) / â9
=7z^14 / 3
2007-12-12 07:34:14 · answer #4 · answered by DizZ 1 · 0⤊ 0⤋
Your expression SQRT (49.z^(28/9)) can be simplified using the properties of exponents. Remember that the square root of a number is the number raised to the 1/2 exponent. so basically your problem is: [49.z^(28/9)] ^ 1/2. Given that the expression in [...] is a multiplication of terms. The exponent can be distributed among them. For example, and expression like ( a. b. c ) ^ d will be equal to (a^d).(b^d).(c^d).
In addition, you will need to remember that exponents multiply each other. For example, take ( e ^ f) ^ g it will result in e ^ (f.g). This should help you solve the problem. Good luck!
2007-12-12 07:42:57 · answer #5 · answered by luisfer_reyes 2 · 0⤊ 0⤋
sq rt (49z^(28/9)) =
7z^(14/3) : - Ans. 'c'.
2007-12-12 07:35:52 · answer #6 · answered by lenpol7 7 · 0⤊ 0⤋
c.
2007-12-12 07:32:17 · answer #7 · answered by Zentraed 4 · 0⤊ 0⤋